2(x+1/x)^2-3(x-1/x)-8=0

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Solution for 2(x+1/x)^2-3(x-1/x)-8=0 equation: 



2(x+1/x)^2-3(x-1/x)-8=0



Domain of the equation: x)^2!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2(+x+1/x)^2-3(+x-1/x)-8=0

We multiply parentheses

2(+x+1/x)^2-3x+3x-8=0

We multiply all the terms by the denominator


2(+x+1-3x*x)^2+3x*x)^2-8*x)^2=0

We add all the numbers together, and all the variables

2(x-3x*x+1)^2+3x*x)^2-8*x)^2=0

Wy multiply elements

3x^3+2(x-3x*x+1)^2=0

We do not support expression: x^3

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